Building on the previously suggested solutions:
// First, checks if it isn’t implemented yet.
if (!String.prototype.format) {
String.prototype.format = function() {
var args = arguments;
return this.replace(/{(d+)}/g, function(match, number) {
return typeof args[number] != ‘undefined’
? args[number]
: match
;
});
};
}
“{0} is dead, but {1} is alive! {0} {2}”.format(“ASP”, “ASP.NET”)
outputs
ASP is dead, but ASP.NET is alive! ASP {2}
If you prefer not to modify String’s prototype:
if (!String.format) {
String.format = function(format) {
var args = Array.prototype.slice.call(arguments, 1);
return format.replace(/{(d+)}/g, function(match, number) {
return typeof args[number] != ‘undefined’
? args[number]
: match
;
});
};
}
Gives you the much more familiar:
String.format(‘{0} is dead, but {1} is alive! {0} {2}’, ‘ASP’, ‘ASP.NET’);
with the same result:
ASP is dead, but ASP.NET is alive! ASP {2}
Current JavaScript
From ES6 on you could use template strings:
let soMany = 10;
console.log(`This is ${soMany} times easier!`);
// “This is 10 times easier!
See Kim’s answer below for details.
Older answer
Try sprintf() for JavaScript.
If you really want to do a simple format method on your own, don’t do the replacements successively but do them simultaneously.
Because most of the other proposals that are mentioned fail when a replace string of previous replacement does also contain a format sequence like this:
“{0}{1}”.format(“{1}”, “{0}”)
Normally you would expect the output to be {1}{0} but the actual output is {1}{1}. So do a simultaneously replacement instead like in fearphage’s suggestion.