If you want the length of an integer as in the number of digits in the integer, you can always convert it to string like str(133) and find its length like len(str(123)).
Without conversion to string
import math
digits = int(math.log10(n))+1
To also handle zero and negative numbers
import math
if n > 0:
digits = int(math.log10(n))+1
elif n == 0:
digits = 1
else:
digits = int(math.log10(-n))+2 # +1 if you don’t count the ‘-‘
You’d probably want to put that in a function 🙂
Here are some benchmarks. The len(str()) is already behind for even quite small numbers
timeit math.log10(2**8)
1000000 loops, best of 3: 746 ns per loop
timeit len(str(2**8))
1000000 loops, best of 3: 1.1 µs per loop
timeit math.log10(2**100)
1000000 loops, best of 3: 775 ns per loop
timeit len(str(2**100))
100000 loops, best of 3: 3.2 µs per loop
timeit math.log10(2**10000)
1000000 loops, best of 3: 844 ns per loop
timeit len(str(2**10000))
100 loops, best of 3: 10.3 ms per loop