Exactly like in JavaScript, you can use the parseInt or parseFloat functions, or simply use the unary + operator:
var x = “32”;
var y: number = +x;
All of the mentioned techniques will have correct typing and will correctly parse simple decimal integer strings like “123”, but will behave differently for various other, possibly expected, cases (like “123.45”) and corner cases (like null).
Table taken from this answer
The Typescript way to do this would be:
Number(‘1234’) // 1234
Number(‘9BX9’) // NaN
as answered here: https://stackoverflow.com/a/23440948/2083492