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You are here: Home / How do I set a variable to the output of a command in Bash?

How do I set a variable to the output of a command in Bash?

August 20, 2021 by James Palmer

In addition to backticks `command`, command substitution can be done with $(command) or “$(command)”, which I find easier to read, and allows for nesting.
OUTPUT=$(ls -1)
echo “${OUTPUT}”

MULTILINE=$(ls
-1)
echo “${MULTILINE}”

Quoting (“) does matter to preserve multi-line variable values; it is optional on the right-hand side of an assignment, as word splitting is not performed, so OUTPUT=$(ls -1) would work fine.

$(sudo run command)

If you’re going to use an apostrophe, you need `, not ‘. This character is called “backticks” (or “grave accent”):
#!/bin/bash

VAR1=”$1″
VAR2=”$2″

MOREF=`sudo run command against “$VAR1” | grep name | cut -c7-`

echo “$MOREF”

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