char is a character and sizeof(char) is defined to be 1. (N1570 6.5.3.4 The sizeof and _Alignof operators, paragraph 4)
char* is a pointer to a character and sizeof(char*) depends on the environment. It is typically 4 in 32-bit environment and 8 in 64-bit environment.
In typical environment where sizeof(char*) > sizeof(char), malloc(sizeof(char*)*len + 1) will (at least try to) allocate more memory than malloc(sizeof(char)*len + 1) if len is small enough not to cause integer overflow.
They are not the same. char* is a pointer to a char. You are misinterpreting char* as a “type” by itself.
char is size 1, and char* which is a pointer can be 4 on 32 bit systems and 8 on 64bit system (provided it is compiled as per the system).