keep.update(yoursequenceofvalues)
e.g, keep.update(xrange(11)) for your specific example. Or, if you have to produce the values in a loop for some other reason,
for …whatever…:
onemorevalue = …whatever…
keep.add(onemorevalue)
But, of course, doing it in bulk with a single .update call is faster and handier, when otherwise feasible.
Define set
a = set()
Use add to append single values
a.add(1)
a.add(2)
Use update to add elements from tuples, sets, lists or frozen-sets
a.update([3,4])
>> print(a)
{1, 2, 3, 4}
If you want to add a tuple or frozen-set itself, use add
a.add((5, 6))
>> print(a)
{1, 2, 3, 4, (5, 6)}
Note: Since set elements must be hashable, and lists are considered mutable, you cannot add a list to a set. You also cannot add other sets to a set. You can however, add the elements from lists and sets as demonstrated with the “.update” method.